SHIFTING
A PLANK WEIGHT 25,09 KG. WHAT
WILL BE THE SHIFT OF IT'S CENTRE
OF GRAVITY IF A
WEIGHT OF 17,24 KG IS PLACED
A DISTANCE OF 3,66 M FROM IT'S ORIGINAL
CG ?
ANSWER :
( a ) THE
CG OF A BODY MOVES PARALLEL TO
THE SHIFT OF THE CG OF ANY
WEIGHT
SHIFTED WITHIN
IT.
( b ) THE DISTANCE
IT MOVES IS EQUAL TO THE WEIGHT
SHIFTED, MULTIPLIED BY THE
SHIFT OF
IT'S CG; ALL DIVIDED BY THE TOTAL
WEIGHT OF THE BODY.
17,24 * 3,66
= 63,09 = 1,49 M
25,09 + 17,24
42,33
QUESTION 23 :
A BEAM CARRIES 2438 KG
AT A DISTANCE OF 1,83 M FROM ONE
END & THE CENTRE OF
GRAVITY OF THE WHOLE MASS
IS 6,09 M FROM THE END. IF THE WEIGHT
OF THE BEAM
ALONE IS 4267,47 KG, WHAT
IS THE DISTANCE OF THE CG
OF THE ORIGINAL BEAM FROM
THE END ?
ANSWER :
GG = w
* d = 2438,55 * 4,26
= 2,43
W
4267,47
2,434 + 6,09 = 8,524
QUESTION 24 :
T P C
FIND THE TONNES PER CENTIMETER
IMMERSION OF A BOX SHAPED VESSEL 64
M LONG BY
10,668 M BREADTH.
ANSWER :
T P C =
1,025 * AREA OF THE WATERPLANE ( A ) = 1,025
* 10,668 * 64,0 = 6,99
100
100
QUESTION 24 : ( METRIC )
WEIGHT OFF THE CENTRE OF FLOTATION
VESSEL'S LENGHT IS 115,82 M,
T P C IS 14,96 TONNES,
M T C IS 330,7 TONNES. CENTRE
OF FLOTATION ON THE CENTRE
LINE.THERE IS 57,9 TONNES REMOVED 39,62 M
AFT OF THE
STERN. ORIGINAL DRAFTS ARE 5,23
M FWD & 5,33 M AFT. FIND NEW
DRAFTS.
ANSWER :
LENGTH =
115,82 = 5791 -- 39,62 = 18,29 M
2
MOMENT TO CHANGE TRIM = W * D = 57,9 * 18,29 = 1058,99
CHANGE OF TRIM
= 1059,99 = 3,20 CM
330,7
REMOVAL OF WEIGHT
THE VESSEL WILL RISE = W =
57,9 = 3,6 CM
T P C 14,96
ORIGINAL DRAFT
RISE
FWD = 0,23 M AFT =
5,33 M
5,30
5,298
TRIM
-0.036
+ 0,036
5.162 M 5,334
M